Template:Elastic moduli

Conversion formulae
Homogeneous isotropic linear elastic materials have their elastic properties uniquely determined by any two moduli among these; thus, given any two, any other of the elastic moduli can be calculated according to these formulas, provided both for 3D materials (first part of the table) and for 2D materials (second part).
3D formulae	<math>K=\,</math>	<math>E=\, </math>	<math>\lambda=\,</math>	<math>G=\, </math>	<math>\nu=\,</math>	<math>M=\,</math>	Notes
<math>(K,\,E)</math>			<math>\tfrac{3K(3K-E)}{9K-E}</math>	<math>\tfrac{3KE}{9K-E}</math>	<math>\tfrac{3K-E}{6K}</math>	<math>\tfrac{3K(3K+E)}{9K-E}</math>
<math>(K,\,\lambda)</math>		<math>\tfrac{9K(K-\lambda)}{3K-\lambda}</math>		<math>\tfrac{3(K-\lambda)}{2}</math>	<math>\tfrac{\lambda}{3K-\lambda}</math>	<math>3K-2\lambda\,</math>
<math>(K,\,G)</math>		<math>\tfrac{9KG}{3K+G}</math>	<math>K-\tfrac{2G}{3}</math>		<math>\tfrac{3K-2G}{2(3K+G)}</math>	<math>K+\tfrac{4G}{3}</math>
<math>(K,\,\nu)</math>		<math>3K(1-2\nu)\,</math>	<math>\tfrac{3K\nu}{1+\nu}</math>	<math>\tfrac{3K(1-2\nu)}{2(1+\nu)}</math>		<math>\tfrac{3K(1-\nu)}{1+\nu}</math>
<math>(K,\,M)</math>		<math>\tfrac{9K(M-K)}{3K+M}</math>	<math>\tfrac{3K-M}{2}</math>	<math>\tfrac{3(M-K)}{4}</math>	<math>\tfrac{3K-M}{3K+M}</math>
<math>(E,\,\lambda)</math>	<math>\tfrac{E + 3\lambda + R}{6}</math>			<math>\tfrac{E-3\lambda+R}{4}</math>	<math>\tfrac{2\lambda}{E+\lambda+R}</math>	<math>\tfrac{E-\lambda+R}{2}</math>	<math>R=\sqrt{E^2+9\lambda^2 + 2E\lambda}</math>
<math>(E,\,G)</math>	<math>\tfrac{EG}{3(3G-E)}</math>		<math>\tfrac{G(E-2G)}{3G-E}</math>		<math>\tfrac{E}{2G}-1</math>	<math>\tfrac{G(4G-E)}{3G-E}</math>
<math>(E,\,\nu)</math>	<math>\tfrac{E}{3(1-2\nu)}</math>		<math>\tfrac{E\nu}{(1+\nu)(1-2\nu)}</math>	<math>\tfrac{E}{2(1+\nu)}</math>		<math>\tfrac{E(1-\nu)}{(1+\nu)(1-2\nu)}</math>
<math>(E,\,M)</math>	<math>\tfrac{3M-E+S}{6}</math>		<math>\tfrac{M-E+S}{4}</math>	<math>\tfrac{3M+E-S}{8}</math>	<math>\tfrac{E-M+S}{4M}</math>		<math>S=\pm\sqrt{E^2+9M^2-10EM}</math> There are two valid solutions. The plus sign leads to <math>\nu\geq 0</math>. The minus sign leads to <math>\nu\leq 0</math>.
<math>(\lambda,\,G)</math>	<math>\lambda+ \tfrac{2G}{3}</math>	<math>\tfrac{G(3\lambda + 2G)}{\lambda + G}</math>			<math>\tfrac{\lambda}{2(\lambda + G)}</math>	<math>\lambda+2G\,</math>
<math>(\lambda,\,\nu)</math>	<math>\tfrac{\lambda(1+\nu)}{3\nu}</math>	<math>\tfrac{\lambda(1+\nu)(1-2\nu)}{\nu}</math>		<math>\tfrac{\lambda(1-2\nu)}{2\nu}</math>		<math>\tfrac{\lambda(1-\nu)}{\nu}</math>	Cannot be used when <math>\nu=0 \Leftrightarrow \lambda=0</math>
<math>(\lambda,\,M)</math>	<math>\tfrac{M + 2\lambda}{3}</math>	<math>\tfrac{(M-\lambda)(M+2\lambda)}{M+\lambda}</math>		<math>\tfrac{M-\lambda}{2}</math>	<math>\tfrac{\lambda}{M+\lambda}</math>
<math>(G,\,\nu)</math>	<math>\tfrac{2G(1+\nu)}{3(1-2\nu)}</math>	<math>2G(1+\nu)\,</math>	<math>\tfrac{2 G \nu}{1-2\nu}</math>			<math>\tfrac{2G(1-\nu)}{1-2\nu} </math>
<math>(G,\,M)</math>	<math>M - \tfrac{4G}{3}</math>	<math>\tfrac{G(3M-4G)}{M-G}</math>	<math>M - 2G\,</math>		<math>\tfrac{M - 2G}{2M - 2G}</math>
<math>(\nu,\,M)</math>	<math>\tfrac{M(1+\nu)}{3(1-\nu)}</math>	<math>\tfrac{M(1+\nu)(1-2\nu)}{1-\nu}</math>	<math>\tfrac{M \nu}{1-\nu}</math>	<math>\tfrac{M(1-2\nu)}{2(1-\nu)}</math>
2D formulae	<math>K_\mathrm{2D}=\,</math>	<math>E_\mathrm{2D}=\, </math>	<math>\lambda_\mathrm{2D}=\,</math>	<math>G_\mathrm{2D}=\, </math>	<math>\nu_\mathrm{2D}=\,</math>	<math>M_\mathrm{2D}=\,</math>	Notes
<math>(K_\mathrm{2D},\,E_\mathrm{2D})</math>			<math>\tfrac{2K_\mathrm{2D}(2K_\mathrm{2D}-E_\mathrm{2D})}{4K_\mathrm{2D}-E_\mathrm{2D}}</math>	<math>\tfrac{K_\mathrm{2D}E_\mathrm{2D}}{4K_\mathrm{2D}-E_\mathrm{2D}}</math>	<math>\tfrac{2K_\mathrm{2D}-E_\mathrm{2D}}{2K_\mathrm{2D}}</math>	<math>\tfrac{4K_\mathrm{2D}^2}{4K_\mathrm{2D}-E_\mathrm{2D}}</math>
<math>(K_\mathrm{2D},\,\lambda_\mathrm{2D})</math>		<math>\tfrac{4K_\mathrm{2D}(K_\mathrm{2D}-\lambda_\mathrm{2D})}{2K_\mathrm{2D}-\lambda_\mathrm{2D}}</math>		<math>K_\mathrm{2D}-\lambda_\mathrm{2D}</math>	<math>\tfrac{\lambda_\mathrm{2D}}{2K_\mathrm{2D}-\lambda_\mathrm{2D}}</math>	<math>2K_\mathrm{2D}-\lambda_\mathrm{2D}</math>
<math>(K_\mathrm{2D},\,G_\mathrm{2D})</math>		<math>\tfrac{4K_\mathrm{2D}G_\mathrm{2D}}{K_\mathrm{2D}+G_\mathrm{2D}}</math>	<math>K_\mathrm{2D}-G_\mathrm{2D}</math>		<math>\tfrac{K_\mathrm{2D}-G_\mathrm{2D}}{K_\mathrm{2D}+G_\mathrm{2D}}</math>	<math>K_\mathrm{2D}+G_\mathrm{2D}</math>
<math>(K_\mathrm{2D},\,\nu_\mathrm{2D})</math>		<math>2K_\mathrm{2D}(1-\nu_\mathrm{2D})\,</math>	<math>\tfrac{2K_\mathrm{2D}\nu_\mathrm{2D}}{1+\nu_\mathrm{2D}}</math>	<math>\tfrac{K_\mathrm{2D}(1-\nu_\mathrm{2D})}{1+\nu_\mathrm{2D}}</math>		<math>\tfrac{2K_\mathrm{2D}}{1+\nu_\mathrm{2D}}</math>
<math>(E_\mathrm{2D},\,G_\mathrm{2D})</math>	<math>\tfrac{E_\mathrm{2D}G_\mathrm{2D}}{4G_\mathrm{2D}-E_\mathrm{2D}}</math>		<math>\tfrac{2G_\mathrm{2D}(E_\mathrm{2D}-2G_\mathrm{2D})}{4G_\mathrm{2D}-E_\mathrm{2D}}</math>		<math>\tfrac{E_\mathrm{2D}}{2G_\mathrm{2D}}-1</math>	<math>\tfrac{4G_\mathrm{2D}^2}{4G_\mathrm{2D}-E_\mathrm{2D}}</math>
<math>(E_\mathrm{2D},\,\nu_\mathrm{2D})</math>	<math>\tfrac{E_\mathrm{2D}}{2(1-\nu_\mathrm{2D})}</math>		<math>\tfrac{E_\mathrm{2D}\nu_\mathrm{2D}}{(1+\nu_\mathrm{2D})(1-\nu_\mathrm{2D})}</math>	<math>\tfrac{E_\mathrm{2D}}{2(1+\nu_\mathrm{2D})}</math>		<math>\tfrac{E_\mathrm{2D}}{(1+\nu_\mathrm{2D})(1-\nu_\mathrm{2D})}</math>
<math>(\lambda_\mathrm{2D},\,G_\mathrm{2D})</math>	<math>\lambda_\mathrm{2D}+ G_\mathrm{2D}</math>	<math>\tfrac{4G_\mathrm{2D}(\lambda_\mathrm{2D} + G_\mathrm{2D})}{\lambda_\mathrm{2D} + 2G_\mathrm{2D}}</math>			<math>\tfrac{\lambda_\mathrm{2D}}{\lambda_\mathrm{2D} + 2G_\mathrm{2D}}</math>	<math>\lambda_\mathrm{2D}+2G_\mathrm{2D}\,</math>
<math>(\lambda_\mathrm{2D},\,\nu_\mathrm{2D})</math>	<math>\tfrac{\lambda_\mathrm{2D}(1+\nu_\mathrm{2D})}{2\nu_\mathrm{2D}}</math>	<math>\tfrac{\lambda_\mathrm{2D}(1+\nu_\mathrm{2D})(1-\nu_\mathrm{2D})}{\nu_\mathrm{2D}}</math>		<math>\tfrac{\lambda_\mathrm{2D}(1-\nu_\mathrm{2D})}{2\nu_\mathrm{2D}}</math>		<math>\tfrac{\lambda_\mathrm{2D}}{\nu_\mathrm{2D}}</math>	Cannot be used when <math>\nu_\mathrm{2D}=0 \Leftrightarrow \lambda_\mathrm{2D}=0</math>
<math>(G_\mathrm{2D},\,\nu_\mathrm{2D})</math>	<math>\tfrac{G_\mathrm{2D}(1+\nu_\mathrm{2D})}{1-\nu_\mathrm{2D}}</math>	<math>2G_\mathrm{2D}(1+\nu_\mathrm{2D})\,</math>	<math>\tfrac{2 G_\mathrm{2D} \nu_\mathrm{2D}}{1-\nu_\mathrm{2D}}</math>			<math>\tfrac{2G_\mathrm{2D}}{1-\nu_\mathrm{2D}} </math>
<math>(G_\mathrm{2D},\,M_\mathrm{2D})</math>	<math>M_\mathrm{2D} - G_\mathrm{2D}</math>	<math>\tfrac{4G_\mathrm{2D}(M_\mathrm{2D}-G_\mathrm{2D})}{M_\mathrm{2D}}</math>	<math>M_\mathrm{2D} - 2G_\mathrm{2D}\,</math>		<math>\tfrac{M_\mathrm{2D} - 2G_\mathrm{2D}}{M_\mathrm{2D}}</math>